∞

To complete the "todo" task described in your code snippet, you need to group the methodInfos list by controllerName and sort each group by a specified sort property. However, from your current code snippet, it isn't clear what the "sort" property refers to since i (which might be a sort index) is used, but its source or increment logic isn't shown in the provided code. Assuming i is a meaningful sort index that you manage elsewhere in your code, here's how you could complete this task using Java Stream API.

meaningful sort index: 有意义的排序索引。在编程和数据处理的上下文中，“meaningful”这个词通常意味着“有意义的”或“有目的的。

Step-by-Step Implementation:

1. Group by controllerName: You can use Java's Collectors.groupingBy to group the list based on the controllerName.
2. Sort within each group: You can then sort each group using Comparator.comparing based on the sort index or any other relevant property.
3. Flatten the grouped and sorted list: If needed, you can flatten the groups back into a single list in the required order.

Here's how you might write the code:

import java.util.*;
import java.util.stream.Collectors;

// Assuming MethodInfo class and other necessary imports are already defined

public class YourClass {

    public void processPermissions(List<String> permissions, Map<String, Method> controllerMethods, Map<String, String> controllerApiTags, Map<String, String> controllerSummaries, String menuId, String icon) {
        List<MethodInfo> methodInfos = new ArrayList<>();
        for (String permission : permissions) {
            String[] parts = permission.split("_");
            String controllerName = parts[0];
            String methodName = parts[1];
            Method method = controllerMethods.get(controllerName + "_" + methodName);
            String apiOperation = method.getAnnotation(ApiOperation.class).value();
            String apiTags = controllerApiTags.get(controllerName);
            String permissionValue = controllerSummaries.get(permission);
            methodInfos.add(new MethodInfo(menuId, controllerName, apiTags, methodName, apiOperation, permissionValue, icon, i)); // Ensure `i` is incremented or managed properly
        }

        // Group by controllerName and sort each group by the index or another property
        Map<String, List<MethodInfo>> groupedMethodInfos = methodInfos.stream()
            .collect(Collectors.groupingBy(MethodInfo::getControllerName));

        List<MethodInfo> sortedMethodInfos = groupedMethodInfo.values().stream()
            .flatMap(group -> group.stream().sorted(Comparator.comparingInt(MethodInfo::getSortIndex))) // Replace getSortIndex with the actual method to obtain the sort value
            .collect(Collectors.toList());

        // Now `sortedMethodInfos` contains all MethodInfo objects, grouped by controllerName and sorted within each group
        
        // Additional logic to use `sortedMethodInfos` can be implemented here
    }
}

Notes:

• Replace MethodInfo::getSort Index with the actual method from your MethodInfo class that returns the sorting index or criteria.
• Ensure that the MethodInfo class has getters for controllerName and other used properties.
• This code assumes that i (used as a sort index in your MethodInfo constructor) is properly managed outside the shown snippet or replaced with a relevant property for sorting.
• Adjust the logic to meet your specific requirements, especially if you need to handle cases where methods or data might be null.

meet: 意为“满足”，这里是满足特定的需求（specific requirements）

This code should help you group and sort methodInfos according to controllerName and a sorting criterion, helping you organize and process your method information effectively.

according to: 意为“根据”或“按照”，用于说明行动或决定是基于何种标准或信息。

new word count: 17